Math, asked by nirupaman21, 8 months ago

DATE:
completing the square method. solve it.
14x2+x-3(using quadratic equations ​

Answers

Answered by bourai244
0

Step-by-step explanation:

14 x^2 + x -3=0

14 x^2/14 + x /14+ -3/14 =0

x^2 + x/14 -3/14 = 0

x^2 +x/14 + (1/28)^2 - 3/14 - (1/28)^2 = 0

(x + 1/28)^2 = (1/28)^2 +3/14

( x+1/28)^2 = 1/784 + 3/14

(x+1/28)^2 = ( 1+ 168)/784

(x+ 1/28)^2 = 169/784

(x+ 1/28) = √(169/784)

x+ 1/28 = +13/28 or -13/28

x = 13/28 -1/28 OR -13/28 -1/28

× = 12/28 OR -14/28

x= 3/7 OR -1/2

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