Question

Date:
Page
10,
2 gram of magnesiome is burst in a closedvessel containing 1.29 gram of oxygen to producemagnesium oxide.
i) Find the limiting reagent .
ii)Calculate the number of
molecules of unreacted reagent left over.
iii) What mass of Mgo is produced.
IV) How many grams of pure HCL are required to neutralize whole MgO produced.


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Answer 1

Answer:

ANSWER

Balanced reaction is:

2Mg+O

2

→2MgO

According to the reaction 2 mol (or 2×24.3=48.6g) Mg reacts with 32 g oxygen. 1 g of Mg requires =

48.6

32

=0.66g oxygen but given oxygen is 0.5 g ∴ oxygen is the limiting reagent

0.5 g oxygen can burn ==

32

48.6

×0.5=0.75g Mg

Excess of Mg left =1−0.75=0.25g

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Answer 2

Explanation:

48 g of Mg requires 32 g of ? requires 0.28 g of

Mass of magnesium required =

But 1 g of Mg is available. Thus, Mg is the excess reagent.

Excess of Mg left behind = 1 - 0.42 = 0.58 g