Question

Date
Page
Find
the sum
sum of all the 11 de roms of am AP whose
most term is 30
middle​

Answer 1

Answer:

See at bottom

Step-by-step explanation:

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Bye

Answer 2

Answer: 330

Step-by-step explanation:

it's a tricky question yet let us try to solve

Ok first of all

We can say that 30 is the Median of 11 terms.

therefore

we know

M = (n + 1)/2 th observation for n = odd

Therefore the 6th term of this AP is 30

Therefore A6 = 30

a + 5d = 30

therefore we need to find S11

Therefore S11 = n/2(2a + (n-1)d)

=11/2(2a + 10d)

=11/2(2(a + 5d)

replacing value

=11/2(2(30))

=11 * 30

=330