Date:
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Let the width of the
rectangle be = x
and length be = 2x
Perimeter of tectangle =albtb)
120 = 2(x + 2x)
120=2(3x
120 = 6x
120
= x
6
2 Oem x
in Area of the length = 2x20
- 40 cm
Wielth = 20cm
Area of the Rectangle = Lxb.
= 40X20
= 800cm
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