Question

DATE
The values of x for
for which the function &
f(x) = x2 - 4x + 1 it decreasing
are​

Answer 1

Function : f(x) = x^2 - 4x + 1

For a function to be decreasing, its first derivative must be non-positive.

f'(x) < 0

(x^2 - 4x + 1)' < 0

2x - 4 < 0

x < 4/2

x < 2

=> x € (-infinity , +2)

The given function is decreasing for all real values of x less than two(2).