david changed f450 into pounds. how many pounds did he receive
Answers
Answer:
Hint: We compare the given equation of circle with general equation of circle x2+y2+2gx+2fy+c=0x2+y2+2gx+2fy+c=0 and find the radius of the circle as g2+f2−c−−−−−−−−−√g2+f2−c. We use the wavy curve method for what values of λλ the radius is less than 5.
Complete step-by-step solution:
We know that the general equation of circle in two variables is given by the equation,
x2+y2+2gx+2fy+c=0x2+y2+2gx+2fy+c=0
We know the radius rr of the above circle is given by
r=g2+f2−c−−−−−−−−−√r=g2+f2−c
We are given the equation from the question with parameter λλ as,
x2+y2+λx+(1−λ)y+5=0x2+y2+λx+(1−λ)y+5=0
We compare the coefficients of xx, coefficients of yy and the constant term of the equation with equation of general circle to have
g=−λ2,f=−(1−λ)2,c=5g=−λ2,f=−(1−λ)2,c=5
So the radius of the circle is given by;
r=(−λ2)2+(−(1−λ)2