Question

David needs a piece of paper where the length is 4 inches more than the width, and the area is as close as possible to 50in^2. To the nearest whole inch, what should the measurements be for the piece of paper?

Answer 1

Answer:

Width=

$- 2 + 3 \sqrt{6} = 5.34847$

Length=

$2 - 3 \sqrt{6} = 9.345$