DE||BC, BD||AC,AB||CD length of BC=5 units,distance between BC and DE is 6 units.find the area of BCED
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BCED is a trapezium
area of trapezium = ar. of square+ ar. of triangle
= 5*6+1/2*1*6
= 30+3
= 33unit^2
area of trapezium = ar. of square+ ar. of triangle
= 5*6+1/2*1*6
= 30+3
= 33unit^2
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