Question

de broglie wavelength for an electron at the 4th orbit of the bohr model of the hydrogen atom is

Answer 1

Given:

Electron's fourth orbit = n = 4

Velocity = V =2.18 × 10`6 Z

To Find:

De Brogile wavelength for an electron

Solution:

Since, n = 4, thus v will be -

V = 0.545 × 10`6

De - Broglie wavelength ,λ = h/p

where h = 6.626 × 0`-34 and

M = mass of electron = 9.1 × 10`-31

Therefore, substituting the values -

= 6.626 × 0` -34 / 9.1 × 10`-31 × 0.545 × 10`6

= 1.33 × 10`-8

Answer: The wavelength of electron in 4th orbit is 1.33 × 10`-8.

Answer 2

✰  Answer :-  ✰

De-broglie wavelength for an electron is given by:

λ = $2\pi R_0$ x $\frac{n}{z}$

✤ Here, n is the orbit number (Here n=4)

✤ z is the atomic number (Here z=1)

Substituting the values, we get:

λ = $2\pi R_0$ x 4

λ = 8πR$_0$