De broglie wavelength of an electron moving with one tenth of the speed of light is
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HEY mate here is your answer...
Mass of an electron =9.1×10−31kg9.1×10−31kg
Speed of the electron = 10% of c = 29979245.829979245.8 (or 30,000,00030,000,000, depends on what c value you take)
Therefore: de Broglie’s wavelength’s formula is λ=hmvλ=hmv.
And so, here the wavelength would be λ=6.62×10−349.1×10−31×29979245.8λ=6.62×10−349.1×10−31×29979245.8
Which would give us 6.62×0.0019.1×29979245.8=2.42×10−11m=0.0242
Mass of an electron =9.1×10−31kg9.1×10−31kg
Speed of the electron = 10% of c = 29979245.829979245.8 (or 30,000,00030,000,000, depends on what c value you take)
Therefore: de Broglie’s wavelength’s formula is λ=hmvλ=hmv.
And so, here the wavelength would be λ=6.62×10−349.1×10−31×29979245.8λ=6.62×10−349.1×10−31×29979245.8
Which would give us 6.62×0.0019.1×29979245.8=2.42×10−11m=0.0242
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