Question

DE is drawn parallel to the base BC of a triangle ABC cutting AB at D and AC at E. If AB=4DB and DC = 2 cm , then AE is equal to:​

Answer 1

In △ADE and △ABC

∠ADE=∠B [corresponding angle]

∠A=∠A

∴△ADE∼△ABC [AA Similarity]

Given AB=4BD

Let BD=x

∴AB=4x i.e, AD=3x

AD/BD=AE/EC⇒3x/x=AE/2

⇒AE=6cm