Question

de parallel bc and bd=ce prove that triangle abc is an isosceles triangle.​

Answer 1

Answer:

We have, DE || BC

Therefore, by BPT, we have,

$AB/BD =AE/EC$

⇒$AD/BD = AE/DB$

$[$∵$BD=CE]$

⇒$AD=AE$

Adding DB on both sides

⇒ AD + DB = AE + DB

⇒ AD + DB = AE + EC  

 [∴ BD = CE]

⇒ AB = AC

⇒ Δ ABC is isosceles