Question

Dear friends i need ur help -*the sum of the digits of a two dist no. is 9,if the digits r reversed,the no. is 63 more than the original. Find the number.(plz answer fast as u can)

Answer 1

Let the two digit number be 10x + y.
Given that the sum of the digits is equal to 9.
Therefore
x + y = 9. (Equation 1)

Also given that if the digits are reversed then the number is 36 more than the original number
Therefore
10y + x = 10x + y + 63
9x - 9y = - 63
Taking 9 as common
x - y = - 7 (Equation 2)

Adding equation 1 and 2
x + y = 9
x - y = - 7

2x = 2
x = 1

2 + y = 9
y = 7

Therefore the number is 10x + y = 10(1) + 7 = 17 


Hope this helps you.

Answer 2

Lagta number X and Y where X in 10th place and Y in unit place
x+y =9---------------------------1
10y+x = 63----------------------2

by elimination method
x+y=9
x+10y=63
= -9y = - 54
y =6

now put in any eqn of y =6
x+y=9
x+6=9
x=3
your number is 36