Dear friends,
Please solve Question no 22.
It's urgent please
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1
The greatest diameter the hemisphere can have i 10cm10cm
T.S.A of the solid = surface area of the cube +CSA of the hemisphere - area of the base of the hemisphere
=6×102+2×22761022227×5×5−22755227×5×555
=600+227×2560022725
=600+78.5760078.57
=678.57cm2678.57cm2
∴ Cost of printing the block at the rate of Rs5/100Rs5100 square is
100sq.cm=5100sqcm5
678.57=?678.57
67.5710067.57100×5=33.93533.93
Hence the amount is Rs.33.93
T.S.A of the solid = surface area of the cube +CSA of the hemisphere - area of the base of the hemisphere
=6×102+2×22761022227×5×5−22755227×5×555
=600+227×2560022725
=600+78.5760078.57
=678.57cm2678.57cm2
∴ Cost of printing the block at the rate of Rs5/100Rs5100 square is
100sq.cm=5100sqcm5
678.57=?678.57
67.5710067.57100×5=33.93533.93
Hence the amount is Rs.33.93
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7
this is your solution okay..^_^
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