Decide 207 in three parts such that all parts are in AP and product of two smaller parts will be 4623
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Answer:
the required parts are : 67,69 and71
Step-by-step explanation:
since all the parts are in A.P
therefore, the numbers are a,a+d and a+2d
by conditon,
a +(a+d) +(a+2d)=207
3a +3d=207
a+d=207/3
a+d=69..........(1)
again,
since the product of two smaller number is 4623
therefore,
a(a+d)=4632
a×69=4632.......from (1)
a= 4633/69
=67
from(1)
d =69-a
=69-67
=2
the required nos are
67,67+2=69,67 +2×2=71
if there is any mistake please give a comment ..i will be very happy to know
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