Math, asked by selena249, 9 months ago

decimal representation of a irrational number cannot be
a) terminating
b) non terminating
c) non terminating repeating
d) all of the above ​

Answers

Answered by Nereida
16

Answer:

The decimal representation of an irrational number is non terminating non repeating repeating.

The question ask about decimal representation that cannot be of an irrational number. Hence, the answer to the question is d) all of the above.

A non terminating decimal representation can also have two types that is either repeating or non repeating.

If the decimal representation is non terminating non repeating, it would signify the decimal representation of an irrational number.

If the decimal representation is non terminating repeating, it was signify the decimal representation of a rational number.

Hence, if only non terminating is written, we cannot judge whether the decimal representation is repeating or non repeating.

Hence it cannot be said if the decimal representation is rational or irrational.

This way, we aren't clear about the option b).

Option a) is for rational numbers.

And option c) is too of rational numbers.

Hence, all the options can not be for Irrational numbers.

Answered by MarshmellowGirl
103

 \large \underline{ \blue{ \boxed{ \bf \green{Required \: Answer}}}}

Decimal Representation of an irrational number cannot be ;

D ) ALL OF THE ABOVE.

 \large \underline{ \blue{ \boxed{ \bf \green{Extra \: Information }}}}

The decimal representation of an irrational number must be non terminating and non repeating .

Here ;

For example, root 2 =1.41421356237309504880168872420969807856......

Because according to the definition ,

If written in decimal notation, an irrational number would have an infinite number of digits to the right of the decimal point, without repetition.

Thus, Options a , b, and c are incorrect and Option d is the correct answer.

Similar questions