Question

Decreasing order of bond order for NO, NO+,NO-

Answer 1

NO+,NO, NO- is the answer

Answer 2

bond order = no.of nonduna electrons- no. of antibonding electrons/2

for NO+

bond order = (8 - 2)/2 = 6/2 = 3... triple bond.

for NO,

bond order= (8-3)/2 = 5 / 2 = 2.5...partial double bond

for NO-,

bond order= (8-4)/2 = 4/2 = 2...double bond