Question

deduce an expression for the orbital velocity of a sateliite revolving around the earth in a curcular orbit at a height 'h' above earth surface

Answer 1

Orbital velocity v=GMR+h=GMR as h<<R

Velocity required to escape

12mv′2=GMmR+h

v′=2GMR+h=2GMR(h<<R)

∴ Increase in velocity

v′−v=2GMR−−−−−√−GMR−−−√

=2qR−−−√−qR−−−√

=qR−−−√(2–√−1)