Physics, asked by veer0336, 5 months ago

Deduce the balancing condition in a Wheatstone bridge​

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Answered by tulipsona26
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Answer:

The Wheatstone's bridge will be in the balanced condition when the current through the galvanometer is zero. Current will divide in magnitude to I1&I2 to go through resistors P and R. When no current flows through galvanometer current I1 will go through P and Q and current I2 will go through R and S.

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