Question

Deduce the dimensional formula of youngs modulus

Answer 1

Young's modulus = Stress/Strain 

                            = F/A x e/l

                            = ma/A x e/l

Where,

F = force

A = area of cross section

e = elongation

l = actual length

a = acceleration 

m = mass                          

 By their units,

                                    Y = [(kg x m/s²) / (m²)] x m/m

                                    Y = (Kg x m) / (m²s²)

                                    Y = Kg/ms²

In dimension formula    Y = [ M L⁻¹ S⁻²]

Answer 2

Explanation:

Young's modulus equation is E = tensile stress/tensile strain = (FL) / (A * change in L), where F is the applied force, L is the initial length, A is the square area, and E is Young's modulus in Pascals (Pa).