Physics, asked by Atul676, 10 months ago

Deduce the following relationship between the focal length f of a spherical mirror distance of object u and distance of image v
1/u+1/v=1/f

Answers

Answered by wwwsanjaydayaramanic
0

Explanation:

For concave mirror:

Let MPN=Concave mirror

P=Pole

F=Principle focus

C=Centre of curvature

PC=Principle axis

AB=Principle acis

A;B'=Real image of object AB formed by concave mirror

DE=Perpendicular drawn from D on the principle axis

In ΔABC and ΔA

B

C

∠ABC=∠A'B'C'(each 90

o

)

∠ACB=∠A'CB'(vertically opposite angles)

Hence,

A

B

AB

=

B

C

CB

........(1)

In ΔDEF and ΔA'B'F

∠DEF=A'B'F(each 90

o

)

∠DFE=A'FB'(vertically opposite angles)

Hence,

A

B

DE

=

FB

EF

But; DE=AB

A

B

AB

=

FB

EF

......(2)

From equation (1) and (2)

B

C

CB

=

F

B

EF

If the aperture of mirror is very small i.e., point E is very near to point P.

Then, EF=PF

B

C

CB

=

FB

PF

PC−PB

PB−PC

=

PB

−PF

PF

......(3)

Applying sign convention, PB=−U,PC=−R=−2f

PB

=−y,PF=−f

Put in equation (3)

−2f+v

−U+2f

=

−v−(−f)

−f

−2f+v

−U+2f

=

−v+f

−f

(−u+2f)(−v+f)=−f(−2f+v)

uv−uf−2fv+2f

2

=2f

2

−fv

uv=uf+2fv−fv

uv=uf+fv

Dividing uvf, we get

uvf

uv

=

uvf

uf

+

uvf

fv

f

1

=

v

1

+

u

1

This is the mirror formula for concave mirror.

(2) For convex mirror:

Let, MPN=convex mirror

P=Pole

F=Principle focus

C=Centre of curvature

PC=Principle axis

AB=Object

A'B'=Image of object AB formed by convex mirror

DE=Perpendicular drawn from point D on the principle axis.

In ΔABC and ΔA'B'C

∠ABC=∠A'B'C(each 90

o

)

∠ACB=∠A'CB'(Common angles)

Hence,

A

B

AB

=

B

C

BC

.....(1)

In ΔDEF and ΔA'B'F

∠DEF=∠A'B'F(each 90

o

)

∠DEF=∠A'FB'(Common angles)

A

B

DE

=

B

F

EF

......(2)

From equation (1) and (2)

B

C

BC

=

B

F

PF

If the aperture of mirror is very small i.e., point E is very near to point P then EF=PF(approx.)

B

C

BC

=

B

F

PF

PC−PB

PB+PC

=

PF−PB

PF

........(3)

Applying sign convention,

PB=−u,PC=+R=+2f

PB

=+v,PF=+f

Put in equation (3),

2f−v

−U+2f

=

f−v

f

(−u+2f)(f−v)=f(2f−v)

−uf+uv+2f

2

=2f

2

−fv

uv=uf+2fv−fv

uv=uf+fv

Dividing uvf, we get

uvf

uv

=

uvf

uf

+

uvf

fv

f

1

=

v

1

+

u

1

This is the mirror formula for convex mirror.

solution

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