Deduce the number of molecules of the following compounds in the given quantities.
32g oxygen, 90g water, 8.8g carbon dioxide, 7.1g chlorine.
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For Oxygen,
Mass = 32 g.
Molar Mass = 32 g.
∵ No. of molecules = Mass/Molar Mass × Avogadro's number.
∴ No. of molecules = 32/32 × 6.022 × 10²³
= 6.022 × 10²³ molecules.
For Water,
Mass = 90 g.
Molar mass = 18 g.
∴ No. of molecules = 90/18 × 6.022 × 10²³
= 5 × 6.022 × 10²³
= 3.011 × 10²⁴ molecules.
For Carbon dioxide,
Mass = 8.8 g.
Molar mass = 44 g.
∴ No. of molecules = 8.8/44 × 6.022 × 10²³
1.2044 × 10²³ molecules.
For Chlorine,
Mass = 7.1 g.
Molar Mass = 71 g.
∴ No. of molecules = 7.1/71 × 6.022 × 10²³
= 6.022 × 10²² molecules.
Hope it helps.
Mass = 32 g.
Molar Mass = 32 g.
∵ No. of molecules = Mass/Molar Mass × Avogadro's number.
∴ No. of molecules = 32/32 × 6.022 × 10²³
= 6.022 × 10²³ molecules.
For Water,
Mass = 90 g.
Molar mass = 18 g.
∴ No. of molecules = 90/18 × 6.022 × 10²³
= 5 × 6.022 × 10²³
= 3.011 × 10²⁴ molecules.
For Carbon dioxide,
Mass = 8.8 g.
Molar mass = 44 g.
∴ No. of molecules = 8.8/44 × 6.022 × 10²³
1.2044 × 10²³ molecules.
For Chlorine,
Mass = 7.1 g.
Molar Mass = 71 g.
∴ No. of molecules = 7.1/71 × 6.022 × 10²³
= 6.022 × 10²² molecules.
Hope it helps.
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