Question

Deduce the number of the following compound in the given quantity 90g water

Answer 1

Answer:

For Oxygen, 

Mass = 32 g.

Molar Mass = 32 g. 

∵ No. of molecules = Mass/Molar Mass × Avogadro's number.  

∴ No. of molecules = 32/32 × 6.022 × 10²³

    = 6.022 × 10²³ molecules. 

For Water, 

Mass = 90 g.

Molar mass = 18 g.

∴ No. of molecules = 90/18 × 6.022 × 10²³

   = 5 × 6.022 × 10²³

   = 3.011 × 10²⁴ molecules. 

For Carbon dioxide, 

Mass = 8.8 g.

Molar mass = 44 g. 

∴  No. of molecules = 8.8/44 × 6.022 × 10²³

    1.2044 × 10²³ molecules. 

For Chlorine, 

Mass = 7.1 g.

Molar Mass = 71 g. 

∴ No. of molecules = 7.1/71 ×  6.022 × 10²³

   =  6.022 × 10²² molecules.

Hope it helps.

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