Question

Deepak can do a work in 18 days he works alone for 6 days and Mohit alone finish the remaining work in 24 days both of them working together can complete in the same work in how many days​

Answer 1

If both Deepak and Mohit are working together then they can complete the same work in 12 days.

Step-by-step explanation:

Deepak alone can do a piece of work in 18 days

So, work done by Deepak in 1 day = $\frac{1}{18}$

He works alone for 6 days

So, work done by Deepak alone for 6 days = $\frac{6}{18}$ = $\frac{1}{3}$

∴ The remaining amount of work to be done will be = 1 – $\frac{1}{3}$ = $\frac{2}{3}$ ← this amount is done by Mohit alone in 24 days.

∴ Mohit alone can do a piece of work in = 24 * ($\frac{3}{2}$ ) = 36 days

So, work done by Mohit in 1-day will be = $\frac{1}{36}$

Therefore,

The work to be done, if both Deepak and Mohit works together to complete the same work, will be given by,

= $\frac{1}{18}$  + $\frac{1}{36}$  

= $\frac{2+1}{36}$

= $\frac{3}{36}$

= $\frac{1}{12}$

Thus, the same amount of work is completed in 12 days if both Deepak and Mohit works together.

----------------------------------------------------------------------------------------

Also View:

A can do a piece of work in 4 days. b can do it in 5 days. with the assistance of c they completed the work in 2 days. find in how many days can c alone do it?

https://brainly.in/question/5201607

Ajsy can do 3/4 th of a,work in 6 days and vijay can do 2/5 of the same work in 4 days. Find the no. Of days in which both.ajay and vijay together can complete the work ?

https://brainly.in/question/7553769