Math, asked by Avirajj6681, 11 months ago

Deepak invested some amount on SI out of Rs 47000 and rest amount on CI for two years. If SI is offering 12% p.a. and CI is offering 15% p.a. compounded annuallyand CI is RS 532.5 more than SI, then find amount invested by deepak on CI?

Answers

Answered by santy2
2

Answer:

The amount invested by Deepak in CI from a sum of 47000 at an interest of 15% for 2 years is 21000.

Step-by-step explanation:

The amount deposited on SI and CI can be given by the following steps:

Step 1: Let x be the amount invested in SI.

Given the total amount invested, the amount invested in CI will be :

= 47000 - x

Step 2: write down the formulas for getting SI and CI.

SI = Principle × rate/100 × Time

CI = Principle [(1 + i)ⁿ - 1]

Step 3: Substitute the values in the formulas above.

SI = x × 12/100 × 2 = 0.24x

CI = (47000 - x) [(1.15)² - 1]

= 47000 - x [1.3225 - 1]

= 47000 - x (0.3225) = 15157.5 - 0.3225x

Step 4: Relate the two interests according to the information in the question. We have that:

SI - CI = 532.5

Step 5 : Apply this relation and solve for x.

15157.5 - 0.3225x - 0.24x = 532.5

-0.5625x = 532.5 - 15157.5

-0.5625x = - 14625

The negatives cancel out.

0.5625x = 14625

x = 14625/0.5625

x = 26000

Step 6: Get the amount invested in CI.

The amount invested in CI is given by :

= 47000 - 26000 = 21000

Answered by SBitupan
3

Answer:

Ans is 21000₹

Step-by-step explanation:

SI for 2 Year=24%

while CI for 2 year =32.25%

Now,

32.25% Of X - 24% of (47000-X)=532.5

or, 56.25% Of X= 532.5 + 11280

or, X = 11812.5/56.25=210

so, 100% of X=21000₹

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