How does the debrogli wavelength for proton and neutron are equal?
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Another name for the de-broglie wavelength is the matter wave
its relations show that the wavelenght is inversely prportional to the momentum of a particle... also the frequency of the matter waves is directly prortional to the total energy
of a particle
λ =h/p
λ=h/mv
v=h/mλ
Kinetic energy = 1/2*mv2
Substituting, K.E = 1/2*h2/mλ2
as we can see, K.E ∝ 1/m
mass of proton = 1.6726 x 10-27 kg
mass of neutron = 1.6749 x 10-27 kg
Therefore, since a proton has a lighter mass, it will have a higher value of kinetic energy.
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Answer:
a proton is a lighter mass, it will have higher value than kinetic energy
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