Question

Deepak is twice as old as his brother vikas. If the difference of their ages be 11years find their present age

Answer 1

Answer:

Step-by-step explanation:

let x be the age of vikas

y be the age of deepak

given

y = 2x ------ 1

y - x = 11

2x - x = 11        (from 1)

x = 11

y = 2x = 2 x 11

y = 22

∴the age of deepak = 22

the age of vikas = 11

hope this helps :)

Answer 2

Answer:

y=11,x=22

Step-by-step explanation:

let age of deepak be x & vikas be y.

x=2y    (1)   by question

x-y=11   (2)

substituting (1) in(2)

2y-y=11

∴ y=11

x = 2y

x = 2 × 11

∴ x = 22

deepak's age is 22

vikas's age is 11