Math, asked by shivaniyadav7954, 2 days ago

Deepika is twice as old as his brother Vikas if the difference of their age be 11 years find their present age

Answers

Answered by Cosmique
38

Answer:

  • Present age of Deepika = 22 yrs
  • Present age of Vikas = 11 yrs

Explanation:

Let,

Present age of Deepika = x

and, Present age of her brother Vikas = y

Then, as given that; Deepika is twice as old as her brother Vikas

therefore,

→ Age of Deepika = 2 ( Age of Vikas )

x = 2 y  ___equation (1)

Also given that; Difference of their ages be 11 yrs

therefore,

→ (Age of Deepika) - (Age of Vikas) = 11

→ x - y = 11

Using equation (1)

→ ( 2 y ) - y = 11

y = 11

Putting value of y in equation (1)

→ x = 2 y

→ x = 2 ( 11 )

→ x = 22

Therefore,

  • Present age of Deepika = 22 yrs. and
  • Present age of Vikas = 11 yrs.
Answered by misscutie94
35

Answer:

✳️ Given ✳️

\mapsto Deepika is twice as old as his brother Vikas. If the difference of their age be 11 years .

✳️ To Find ✳️

  • \mapsto What is the value of their present age.

✳️ Solution ✳️

✒️ Let the present age of Vikas be x years

✒️ Since, Deepika is twice as old as Vikas, then the present age of Deepika will be 2x years

According to the question ,

\implies 2x - x = 11

\dashrightarrow x = 11

\therefore ✴️ Present age of Vikas = 11 years.

✴️ Present age of Deepika = 2x = 2(11) = 22 years.

________________________

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