# Q.20 A driver accelerates his car first at the rate of 2.8 m/s2 and then at the rate of 1.4 m/s2.The ratio of two force exerted by the engine in two cases will be?

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## Given:-

First case:

**Acceleration**** ****=**** ****2****.****8**** ****m****/****s²**

Second case:

**Accele****ration**** ****=**** ****1****.****4**** ****m****/****s²**

**[****Hint**** ****by ****Imperius****:**** **Mass of an object always remains same. Weight varies.**]**

**To**** ****Find****:****-**

**Ratio**** ****of**** ****t****wo**** ****forces**** ****exertee**** ****by**** ****the**** ****Engine**** ****in**** ****two**** ****cases****.**

Let the mass of the car be = **m**

We know,

**Force**** ****=**** ****Mass**** ****×**** ****Accele****ration**

**Case**** ****1****:****-**

Force (F′) = **m**** ****×**** ****2****.****8**** ****m****/****s²**** ****=**** ****(**** ****2****.****8****m**** ****)****m****/****s²**

**Case**** ****2****:****-**

Force (F″) = **m**** ****×**** ****1****.****4**** ****m****/****s²**** ****=**** ****(**** ****1****.****4****m**** ****)**** ****m****/****s²**

**Finding**** ****rat****io**** ****of**** ****the**** ****forces**** ****in**** ****two**** ****cases****:****-**

**RATIO****:****-**

**Therefor****e****,**** ****ratio**** ****b****/****w**** ****the**** ****two**** ****cases**** ****will**** ****be**** ****1**** ****:**** ****2****.**

**@****I****m****p****e****r****i****u****s**

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