Deer starts from rest after seeing a tiger, and its acceleration – time graph is drawn as shown. Plot the corresponding velocity – time graph also plot displacement – time graph. Support your answer with proper explanation
Answers
Answer:
Figure (i) represents a velocity-time graph when the body starts from rest, and its velocity increases at a uniform rate.
The slope of the graph AC. i.e.,
BC
AB
gives the acceleration of body.
∴Acceleration=
Total time
change in velocity
=
5s
(16−0)ms
−1
=3.2ms
−2
The area of triangle ABC, gives the displacement.
Thus, displacement in 5 s
2
1
×AB×BC=
2
1
×16ms
−1
×5s
=40m
Figure (ii) represents velocity - time graph, where the body is initially not at rest.
The slope of graph AC, i.e., (
BC
AB
) gives the acceleration.
∴Acceleration=
BC
AB
4s
(25−5)ms
−1
=
4
20
ms
−2
=5ms
−2
The distance covered by the body in specified direction is area of trapezium ECAD.
∴Displacement=
2
1
(CE+AD)×ED
=
2
1
(5+25)ms
−1
×4s=60m
Answered By 0mk@r
Explanation:
please mark as brainliess