Question

Deetermine k,8k square+4k-8=0

Answer 1

Answer:

${8k}^{2} + 4k - 8 = 0 \\ {2k}^{2} + k - 2 = 0 \\ discriminant \: d = {b}^{2} - 4ac \\ = {1}^{2} - 4 \times 2 \times ( - 2) \\ = 1 + 16 \\ = 17 \\ so \: solution \: is \: \\ x = \frac{ - b + \sqrt{d} }{2a} \: or \: \frac{ - b - \sqrt{d} }{2a} \\ x = \frac{ - 1 + \sqrt{17} }{4} \: or \: \frac{ - 1 - \sqrt{17} }{4}$

Answer 2

Answer:

this is correct....................