∆DEF and ∆ PQR, which of these gives the correct correspondence of the congruence of the triangle, if DF = 3.5 cm, EF = 3cm, PQ = 3.5 cm, QR = 3cm, ∠DFE = 40o and ∠PQR = 40o?
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Step-by-step explanation:
- DF = PR
- EF = QR
- <F = <R
- <DEF = <PQR ( by SAS property)
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