Question

def f(n): s=0 for i in range(1,n+1): if n%i == 0: s = s+1 return(s%2 == 1) The function f(n) given above returns True for a positive number n if and only if:​

Answer 1

Answer:

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Explanation:

Answer 2

"n is a perfect square" is the correct answer for the above question

Explanation:

• The above question code is in python language If the input given by the user is a perfect square, then the output is "true" otherwise "false" is returned by the function "f".
• It is because the above function "f" firstly counts the number of factors for any number.
• Then it checks that the total factor is a (multiple of 2)+1 or not, if it is (multiple of 2)+1, then it will be definitely a perfect square of any number.
• So it returns true if the factor of any number is (multiple of 2)+1 otherwise it returns false.

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• Python : https://brainly.in/question/14689905