Question

def g(x):
(q,d) = (1,0)
while q <= x:
(q,d) = (q*10,d+1)
return(d)

Answer 1

q is multiplied with 10 every time until it is bigger than x. d counts the number of times the q is multiplied. so in the end d = 8 and q = 100000000.

def g(x):

   (q, d) = (1, 0)

   while q <= x:

       (q, d) = (q * 10, d + 1)

   return(d)

#  What does g(31415927) return

print(g(31415927))   #  -> 8

print(g(1234567890)) #  -> 10

Please look at this: https://code.sololearn.com/cbrQ0BItZ2mj/?ref=app#py

Answer 2

Given:

g(31415927)

( q, d ) = ( 1, 0 )

Condition:  

q <= x

Then,

( q , d ) = ( q * 10, d + 1 )

Solution:

The loop returns a value if q > 31415927

When d = 8,

The value of q = 100000000 and so q > 31415927

Hence,  the function returns 8.

Read more on Brainly.in - https://brainly.in/question/5266216