Question

∆DEF is an isosceles triangle in which DE=DF and angle DEF=60°. Find angle EAF.

Answer 1

Answer:

Step-by-step explanation:

DEF = 60

IN TRIANGLE DEF

ANGLES DEF AND EFD AND FDE ADD UP TO 180

DEF= DFE (SINCE DEF IS AN ISOCELOS TRIANGLE)

2 X DEF + EDF=180

120+ EDF=180

EDF=60

IN CYCLIC QUADILATERAL EAFD

ANGLES EAF + FAE = 180

SINCE EAF =120

120+FAE=180

FAE= 60

Answer 2

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