DEF ki racana kijiye taki DE=5c.m. and DF=3c.m.and EDF= 900
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Answer:
To construct: △DEF where DE=5cm,DF=3cm and m∠EDF=90
o
.
Steps of construction:
(a) Draw a line segment DF=3cm
(b) At point D an angle of 90
o
with the help of compass i.e., ∠XDF=90
o
.
(c) Taking D as centre, draw an arc of radius 5cm, which cuts DX at the point E
(d) Join EF
It is the required right angle triangle DEF
Explanation:
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