Question

Define Avogadro’s constant and calculate the number of particles present in 56g of N2

molecule​

Answer 1

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Molar mass, that is the mass of one mole of N2 gas is 28g. One mole of any substance contains 6.023 X 1023 particles. Hence, there are 6.023 X 1023 molecules of N2 in 28g of N2. Thus

28 g of N2 = 6.023 X 1023 molecules of N2

1 g of N2 = (6.023 X 1023 / 28) molecules of N2

So 56 g of N2 = [(6.023 X 1023 X 56) / 28] molecules of N2

= 12.046 X 10²³ molecules of N2.

Answer 2

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Molar mass, that is the mass of one mole of N2 gas is 28g. One mole of any substance contains 6.023 X 1023 particles. Hence, there are 6.023 X 1023 molecules of N2 in 28g of N2. Thus

28 g of N2 = 6.023 X 1023 molecules of N2

1 g of N2 = (6.023 X 1023 / 28) molecules of N2

So 56 g of N2 = [(6.023 X 1023 X 56) / 28] molecules of N2

= 12.046 X 10²³ molecules of N2.