define gravitational field & gravitational intensity at a point
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Gravitational Field and Intensity
The space around a body where the gravitational force exerted by it can be experienced by any other particle is known as the gravitational field of the body. The strength of this gravitational field is referred to as intensity, and it varies from point to point.
Consider the gravitational field of a particle of mass m located at the origin (O).
Suppose that a test particle of mass m0 is placed at the point P(x, y, z). The force of gravitational attraction exerted on the test particle is given by,
g = (GMmo/r2) 
where the position vector  = r,
r = OP = || = || = r
and the unit vector,  =  / r
The intensity of this gravitational field at a point (P) is given by the force per unit mass on a test particle kept at P, i.e.
 = g/mo

where  is the gravitational intensity and g is the gravitational force acting on the mass m0. The gravitational field is, therefore, a vector field.
The gravitational field at P due to a particle of mass m kept at the point O (origin) is given by
 = g/mo = {-(Gmmo/r2)} * 1/mo = Gm/r2 
where  = xi + yj + zk represents the position vector of the point P with respect to the source at the origin and  =  / r represents the unit vector along the radial direction.
The superposition principle extends to gravitational field (intensities) as well:
 = 1 + 2 + 3 +....+ n
where1, 2,.... n are the gravitational field intensities at a point due to particle 1, 2, ......, n respectively.
For a continuously distributed mass, the formula changes to  =∫d, where d gravitational field intensity due to an elementary mass dm.
The gravitational field of a ring on its axis
Let us consider a ring of mass M in the plane perpendicular to the plane of the paper. We want to find the gravitational field on its axis at a distance x.
Consider a differential length of the ring of mass dm.
dE = Fdm/z2

The Y-components of the fields due to diametrically opposite elements cancel each other. Thus, the X-components add up.
E = ∫Gdm/z2 cosα = Gcosα/z2 ∫dm = GMcosα/z2 = GMx/(a2+x2)3/2 ←
The space around a body where the gravitational force exerted by it can be experienced by any other particle is known as the gravitational field of the body. The strength of this gravitational field is referred to as intensity, and it varies from point to point.
Consider the gravitational field of a particle of mass m located at the origin (O).
Suppose that a test particle of mass m0 is placed at the point P(x, y, z). The force of gravitational attraction exerted on the test particle is given by,
g = (GMmo/r2) 
where the position vector  = r,
r = OP = || = || = r
and the unit vector,  =  / r
The intensity of this gravitational field at a point (P) is given by the force per unit mass on a test particle kept at P, i.e.
 = g/mo

where  is the gravitational intensity and g is the gravitational force acting on the mass m0. The gravitational field is, therefore, a vector field.
The gravitational field at P due to a particle of mass m kept at the point O (origin) is given by
 = g/mo = {-(Gmmo/r2)} * 1/mo = Gm/r2 
where  = xi + yj + zk represents the position vector of the point P with respect to the source at the origin and  =  / r represents the unit vector along the radial direction.
The superposition principle extends to gravitational field (intensities) as well:
 = 1 + 2 + 3 +....+ n
where1, 2,.... n are the gravitational field intensities at a point due to particle 1, 2, ......, n respectively.
For a continuously distributed mass, the formula changes to  =∫d, where d gravitational field intensity due to an elementary mass dm.
The gravitational field of a ring on its axis
Let us consider a ring of mass M in the plane perpendicular to the plane of the paper. We want to find the gravitational field on its axis at a distance x.
Consider a differential length of the ring of mass dm.
dE = Fdm/z2

The Y-components of the fields due to diametrically opposite elements cancel each other. Thus, the X-components add up.
E = ∫Gdm/z2 cosα = Gcosα/z2 ∫dm = GMcosα/z2 = GMx/(a2+x2)3/2 ←
steeve:
this answer is copied u must remove the objects
what is this obj?
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gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.
and
The gravitational field intensity (EG) or (g) is the force on a unit mass at a point in the field. Since the force (F) on a body of mass m in a gravitational field of a body of mass M = GMm/r2 you can see that the force per unit mass is given by F/m.
HOPE IT HELPS YOU
and
The gravitational field intensity (EG) or (g) is the force on a unit mass at a point in the field. Since the force (F) on a body of mass m in a gravitational field of a body of mass M = GMm/r2 you can see that the force per unit mass is given by F/m.
HOPE IT HELPS YOU
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