Question

Define: how long will it take a force of 10n to stop a mass of 2.5kg which is moving at 20m/s

Answer 1

force = mass * acceleration
10n = 2.5 kg * a
10/2.5 =a
100/25 =a
4 m per s = acceleration
So here v =0
U = 20 m per s
Using v =u+at
V-u/a =t
0-20/4 =t
5 sec =t

Answer 2

Answer:

force applied(F)= -10N (since the force is acting in the opp. direction of motion or opposing the motion)

mass of body(m)=2.5kg

initial velocity of body(u)=20m/s

final velocity of body(v)=0m/s

According to newton's seond law of motion

F=ma

-10=2.5*a

-10/2.5=v-u/t (since a=v-u/t)

-4t=0-20

t=-20/-4

t=5 second.