Define kinetic energy. obtain an expression for the kinetic energy of an object
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energy which a body possesses by virtue of being in motion.
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Hello friend
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Let's start,
Definition: The energy which an object has because of its motion is called it's kinetic energy.
Suppose a stationary object of mass m moves because of an applied force.Let u be its initial velocity (here u = 0).Let the applied force be F . This generates an acceleration a in the object,and after time t, the velocity of the object becomes equal to v. The Displacement during this time is s. The work done on the object,
W = Fs
W = F x s
So,according to Newton's second law of motion,
F = ma. ............(1)
Similarly,
using Newton's second equation of motion
s = ut + 1/2 at^2
s = 1/2at^2 .....................(2)
W = ma x 1/2at^2. .......(using equation (1) and (2)
W = 1/2m x (at)^2 .............(3)
Using Newton's first equation of motion
v = u + at
v = 0 + at
v = at
v^2 = a^2 t^2 = (at^2).........(4)
W = 1/2mv^2 .........(using equation (3) and (4)
The kinetic energy gained by an object is the amount of work done on the object.
hence,
K.E = W
K.E = 1/2mv^2
Now take an example based on Kinetic energy.
eg.. A stone having a mass of 250gm is falling from a height.How much kinetic energy does it have at the moment when it's Velocity is 2m/s.?
=) Given :
Mass of the object,m = 250g
mass is given into gram so we will write it into kg.
So 1 kg = 1000g.
m = 250/100 .
Velocity of the object = 2m/s.
We have to find, the kinetic energy of the object,
So,we know that,
Kinetic energy. = 1/2mv^2
By putting the values,we get
kinetic energy = 1/2 x 250/1000 x (2)^2
kinetic energy = 25/100 x 2
kinetic energy = 50/100
kinetic energy = 0.5 J.
I hope this will helps you.
Thanks .
----------------
----------------
Let's start,
Definition: The energy which an object has because of its motion is called it's kinetic energy.
Suppose a stationary object of mass m moves because of an applied force.Let u be its initial velocity (here u = 0).Let the applied force be F . This generates an acceleration a in the object,and after time t, the velocity of the object becomes equal to v. The Displacement during this time is s. The work done on the object,
W = Fs
W = F x s
So,according to Newton's second law of motion,
F = ma. ............(1)
Similarly,
using Newton's second equation of motion
s = ut + 1/2 at^2
s = 1/2at^2 .....................(2)
W = ma x 1/2at^2. .......(using equation (1) and (2)
W = 1/2m x (at)^2 .............(3)
Using Newton's first equation of motion
v = u + at
v = 0 + at
v = at
v^2 = a^2 t^2 = (at^2).........(4)
W = 1/2mv^2 .........(using equation (3) and (4)
The kinetic energy gained by an object is the amount of work done on the object.
hence,
K.E = W
K.E = 1/2mv^2
Now take an example based on Kinetic energy.
eg.. A stone having a mass of 250gm is falling from a height.How much kinetic energy does it have at the moment when it's Velocity is 2m/s.?
=) Given :
Mass of the object,m = 250g
mass is given into gram so we will write it into kg.
So 1 kg = 1000g.
m = 250/100 .
Velocity of the object = 2m/s.
We have to find, the kinetic energy of the object,
So,we know that,
Kinetic energy. = 1/2mv^2
By putting the values,we get
kinetic energy = 1/2 x 250/1000 x (2)^2
kinetic energy = 25/100 x 2
kinetic energy = 50/100
kinetic energy = 0.5 J.
I hope this will helps you.
Thanks .
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