Physics, asked by Anonymous, 10 hours ago

Define magnification produced by a spherical mirror in terms of height of a object and image. How is it related to object and image distance? Explain why magnification is positive for virtual image and negative for real image.​

Answers

Answered by mishri1b
3

Answer:

It is the ratio of the height of the image to the height of the object and is denoted as m. The magnification, m produced by a spherical mirror can be expressed as: m=h′h where h′ is height of image and h is height of object. It is also equal to the negative of the ratio of the image distance(v) to object distance (u).

Explanation:

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Answered by 231001ruchi
1

 

Magnification is the ratio of height of the image(h') to the height of the object(h).It is also equal to negative of the ratio of the image distance(v) to object distance(u).m = hh′=−uvReal image is always formed in front of the mirror and virtual image is formed behind the mirror. Object distance is always negative(according to convention). When the magnification is positive, that means image distance ispositive or the image is formed behind the mirror. So it is virtual. And when the magnification is negative, that means image distance is pnegative or the image is formed in front of the mirror. So it is real.

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