Question

Define oxidation and reduction on the basis of. mno2+4hcl-mncl2+2h2o+cl2​

Answer 1

In the reaction
MnO2 +4HCl———->MnCl2+2H2O+Cl2.

Here MnO2 is reduced to MnCl2.
ie.,
the oxidation no.of Mn is decreased from +4 to -2.
HCl is oxidised to chlorine molecule.
ie.,
the OXIDATION-NUMBER of chlorine is increased from -2 to 0.

So MnO2 is reduced to MnCl2.
HCl is oxidised to chlorine. Ok

Answer 2

In the reaction

MnO2 +4HCl———->MnCl2+2H2O+Cl2.

Here MnO2 is reduced to MnCl2.

ie.,

the oxidation no.of Mn is decreased from +4 to -2.

HCl is oxidised to chlorine molecule.

ie.,

the OXIDATION-NUMBER of chlorine is increased from -2 to 0.

So MnO2 is reduced to MnCl2.

HCl is oxidised to chlorine.

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PLZ MARK AS BRANLIEST