Question

Define resolving power of an optical instrument. How does it depend on wavelength ?

Answer 1

$\textbf{resolving power}$ is the ability of an optical instruments to sperate or distinguish closely adjacent image.

resolving power is given by,
$\theta=1.22\frac{\lambda}{D}$

where $\theta$ denotes resolving power of instrument, $\lambda$ is wavelength of the light emitting from the source and D is the diameter of aperture of objective lens.

hence, it is clear that, resolving power is directly proportional to wavelength of light emitting from the source.

Answer 2

Resolving power of optical instruments :

➡️Resolving power of optical instruments is a ability to produce a distinct separate images of 2 closely lying point Object.

➡️It is the reciprocal of limit of resolution of optical instruments.