Define the distance of the closest approach an alpha particle of kinetic energy k is bombarded on a thin gold fuel find the distance of the closest approach in our what will be the distance of the closest approach for an alpha particle of double the kinetic energy
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Distance of closest approach when the alpha particle
moves towards the nucleus , it's kinetic energy keeps on decreasing because kinetic energy is being consumed in doing work against the force of nucleus at which velocity of the alpha particle become zero is known as the distance of closest approach
Distance of closest approach is given as
2z2e /4π€o
or distance of closest approach prop
1/K
or r1/re = k2/K1
or r2 =k1/k2 ×r1
=k/2k×r
=r/2
Hence the distance of closest approach would be r/2
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. It was necessary to define a new unit, "Light Year" to measure distances due to the distances between objects being exceedingly large
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