Question

define the period of the satellite and prove that the square of the period of the satellite directional proportional the cube of radius of satellite​

Answer 1

Answer:

We know,

orbital velocity of satellite is given by

where G is gravitational constant, M is mass of earth and r is the radius of circular orbit.

but we know, when a particle moves in circular path of radius r, then orbital velocity of the particle is given by , , here T is time period.

squaring both sides,

here it is clear that

e.g., the square of the period of revolution of a satellite is directly proportional to the cube of the orbital radius

Explanation:

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