Question

define the velocity and acceleration of your particle moving in an incident plane​

Answer 1

Answer:-

parabola

Explanation:-

A particle moves with constant acceleration in a direction different from initial velocity.

Let the velocity be v, acceleration be a, angle between them is θ [θ<90

0

]

Component of Velocity in the Direction of a is vcosθ and in a direction perpendicular to a is vsinθ

From equations of Kinematics,

In the direction of acceleration,

y=vcosθt+

2

1

at

2

−−−−−−(1)

In the direction perpendicular to acceleration,

x=vsinθt

t=

vsinθ

x

−−−−−−−−(2)

Substituting 2 in 1, we get:

y=vcosθ(

vsinθ

x

)+

2

1

a(

sin

2

θ

x

2

)

y=

tanθ

x

+

2

1

a

sin

2

θ

x

2

This is in the form of a parabola: y=Ax

2

+Bx+C.

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