define the velocity and acceleration of your particle moving in an incident plane
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Answer:-
parabola
Explanation:-
A particle moves with constant acceleration in a direction different from initial velocity.
Let the velocity be v, acceleration be a, angle between them is θ [θ<90
0
]
Component of Velocity in the Direction of a is vcosθ and in a direction perpendicular to a is vsinθ
From equations of Kinematics,
In the direction of acceleration,
y=vcosθt+
2
1
at
2
−−−−−−(1)
In the direction perpendicular to acceleration,
x=vsinθt
t=
vsinθ
x
−−−−−−−−(2)
Substituting 2 in 1, we get:
y=vcosθ(
vsinθ
x
)+
2
1
a(
sin
2
θ
x
2
)
y=
tanθ
x
+
2
1
a
sin
2
θ
x
2
This is in the form of a parabola: y=Ax
2
+Bx+C.
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