Physics, asked by ayushgwari088, 11 months ago

Define v^2=u^2+2as without graph

Answers

Answered by Rohankiratsata
1

1st step:

velocity=distance/time traveled

v  = s \div t

2nd step:

acceleration = rate \: of \: Δv \div t

initial \: velocity \:  = u

a = Δv \div t \\ a = (v - u) \div t \\ at = (v - u) \\ v = u + at \:  -  -  - (eq.1)

3rd step:

average \: velocity = v + u \div 2 \\ apply \: v = s \div t \\ s = vt \\ subtitute \:  the \: average \: velocity  s =( (v  + u) \div 2)t

average \:  velocity =(v+u)/2  \: \\ \:  apply  \: v=s/t  \\ s=vt \:  \\  subtitute \:  the  \: average \:  velocity  \:  \: s=[(v+u)/2]t

SUBSTITUTE EQ.1

s=[(at+u+u)/2]t  \\ </p><p>s=[(at+2u)/2]t \:  \\substitute \:  s=[at/2+u]t  \\ </p><p>s={at}^{2}/2+tu \:  -  -  -  -  -  - (2)

4th step:

eq'n 1; (v=u+at) = (v=u+at)²

v²=(u+at)²⇔expand

v²=u²+2atu+a²t²⇔factor 2a

v²=u²+2a(tu+at²/2)⇔eq'n 2

v²=u²+2as

I HOPE THIS HELPS...

THANKS...PLEASE MAKE IT BRILLIANT

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