Question

Define x square+ 8x square-7x-2 as a factor fo x-1

Answer 1

Answer:

${x}^{2} + 8x {}^{2} - 7x - 2 \\ = 9 {x}^{2} - 7x - 2 \\ = 9 {x}^{2} - 9x + 2x - 2 \\ = 9x (x - 1) + 2(x - 1) \\ = (x - 1)(9x + 2) \\ hence \: (x - 1) \: is \: a \: factor \: of \: the \: given \: equation$

Step-by-step explanation:

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