Question

The LCM and HCF of two numbers are 1760 and 32 respectively, if one number is 160. Find the other

Answer 1

Answer:

as we know that LCM × HCF = PRODUCT OF THE NO.S

let the other no. be 'x'

Step-by-step explanation:

LCM= 1760

HCF=32

ONE NO.=160

∴ 1760 × 32= 160× (x)

⇒ 56320 = 160x

⇒56320÷160=x

⇒352=x

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Answer 2

Given:

The LCM and HCF of the two numbers are 1760 and 32 respectively. Out of two numbers, one number is 160.

To find:

The other number.

Solution:

As we know, the product of two numbers 'a' and 'b' is equal to the product of their LCM and HCF.

Thus, we have

$a \times b = LCM \times HCF$

As given, one of the numbers is 160, LCM = 1760 and HCF = 32. So, we have

$160 \times b = 1760 \times 32$

$b = \frac{1760 \times 32}{160}$

$b = 176 \times 2$

$b = 352$

Hence, the other number is 352.