definie time of flight horizontal range and maximum height attained by a projectile. illustrate with diagram
Answers
Answered by
2
Explanation:
Time taken by the projectile to reach the half of maximum height is the solution of following quadratic equation:
H/2 = (u.sinx)t - (g/2).t^2.
where, H = Maximum Height = (u sinx)^2/(2g).
The two roots of this equation are two values of time when the height achieves by body in projectile motion is half of its maximum height.
One of the root corresponds to time when the given height is achieved during upward motion and other root corresponds to the same during downward motion.
plz foll ow me I will also foll ow back
Attachments:
Similar questions